3/5y+12+42=140

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Solution for 3/5y+12+42=140 equation: 



3/5y+12+42=140

We move all terms to the left:

3/5y+12+42-(140)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



We add all the numbers together, and all the variables

3/5y-86=0

We multiply all the terms by the denominator


-86*5y+3=0

Wy multiply elements

-430y+3=0

We move all terms containing y to the left, all other terms to the right

-430y=-3

y=-3/-430

y=3/430

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