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3/5x=8x
We move all terms to the left:
3/5x-(8x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-8x+3/5x=0
We multiply all the terms by the denominator
-8x*5x+3=0
Wy multiply elements
-40x^2+3=0
a = -40; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-40)·3
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*-40}=\frac{0-4\sqrt{30}}{-80} =-\frac{4\sqrt{30}}{-80} =-\frac{\sqrt{30}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*-40}=\frac{0+4\sqrt{30}}{-80} =\frac{4\sqrt{30}}{-80} =\frac{\sqrt{30}}{-20} $
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