3/5x-5x+60=7

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Solution for 3/5x-5x+60=7 equation:



3/5x-5x+60=7
We move all terms to the left:
3/5x-5x+60-(7)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
We add all the numbers together, and all the variables
-5x+3/5x+53=0
We multiply all the terms by the denominator
-5x*5x+53*5x+3=0
Wy multiply elements
-25x^2+265x+3=0
a = -25; b = 265; c = +3;
Δ = b2-4ac
Δ = 2652-4·(-25)·3
Δ = 70525
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{70525}=\sqrt{25*2821}=\sqrt{25}*\sqrt{2821}=5\sqrt{2821}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(265)-5\sqrt{2821}}{2*-25}=\frac{-265-5\sqrt{2821}}{-50} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(265)+5\sqrt{2821}}{2*-25}=\frac{-265+5\sqrt{2821}}{-50} $

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