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3/5x-4/6x=-5
We move all terms to the left:
3/5x-4/6x-(-5)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
3/5x-4/6x+5=0
We calculate fractions
18x/30x^2+(-20x)/30x^2+5=0
We multiply all the terms by the denominator
18x+(-20x)+5*30x^2=0
Wy multiply elements
150x^2+18x+(-20x)=0
We get rid of parentheses
150x^2+18x-20x=0
We add all the numbers together, and all the variables
150x^2-2x=0
a = 150; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·150·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*150}=\frac{0}{300} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*150}=\frac{4}{300} =1/75 $
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