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3/5x-2=-x+1
We move all terms to the left:
3/5x-2-(-x+1)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-(-1x+1)-2=0
We get rid of parentheses
3/5x+1x-1-2=0
We multiply all the terms by the denominator
1x*5x-1*5x-2*5x+3=0
Wy multiply elements
5x^2-5x-10x+3=0
We add all the numbers together, and all the variables
5x^2-15x+3=0
a = 5; b = -15; c = +3;
Δ = b2-4ac
Δ = -152-4·5·3
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{165}}{2*5}=\frac{15-\sqrt{165}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{165}}{2*5}=\frac{15+\sqrt{165}}{10} $
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