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3/5x-1=2/4x+5
We move all terms to the left:
3/5x-1-(2/4x+5)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x+5)!=0We get rid of parentheses
x∈R
3/5x-2/4x-5-1=0
We calculate fractions
12x/20x^2+(-10x)/20x^2-5-1=0
We add all the numbers together, and all the variables
12x/20x^2+(-10x)/20x^2-6=0
We multiply all the terms by the denominator
12x+(-10x)-6*20x^2=0
Wy multiply elements
-120x^2+12x+(-10x)=0
We get rid of parentheses
-120x^2+12x-10x=0
We add all the numbers together, and all the variables
-120x^2+2x=0
a = -120; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-120)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-120}=\frac{-4}{-240} =1/60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-120}=\frac{0}{-240} =0 $
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