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3/5x-1/6x-26=23
We move all terms to the left:
3/5x-1/6x-26-(23)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
3/5x-1/6x-49=0
We calculate fractions
18x/30x^2+(-5x)/30x^2-49=0
We multiply all the terms by the denominator
18x+(-5x)-49*30x^2=0
Wy multiply elements
-1470x^2+18x+(-5x)=0
We get rid of parentheses
-1470x^2+18x-5x=0
We add all the numbers together, and all the variables
-1470x^2+13x=0
a = -1470; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-1470)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-1470}=\frac{-26}{-2940} =13/1470 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-1470}=\frac{0}{-2940} =0 $
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