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3/5x-(x-2)=-2
We move all terms to the left:
3/5x-(x-2)-(-2)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-(x-2)+2=0
We get rid of parentheses
3/5x-x+2+2=0
We multiply all the terms by the denominator
-x*5x+2*5x+2*5x+3=0
Wy multiply elements
-5x^2+10x+10x+3=0
We add all the numbers together, and all the variables
-5x^2+20x+3=0
a = -5; b = 20; c = +3;
Δ = b2-4ac
Δ = 202-4·(-5)·3
Δ = 460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{115}}{2*-5}=\frac{-20-2\sqrt{115}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{115}}{2*-5}=\frac{-20+2\sqrt{115}}{-10} $
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