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3/5x+5=x-5
We move all terms to the left:
3/5x+5-(x-5)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
3/5x-x+5+5=0
We multiply all the terms by the denominator
-x*5x+5*5x+5*5x+3=0
Wy multiply elements
-5x^2+25x+25x+3=0
We add all the numbers together, and all the variables
-5x^2+50x+3=0
a = -5; b = 50; c = +3;
Δ = b2-4ac
Δ = 502-4·(-5)·3
Δ = 2560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2560}=\sqrt{256*10}=\sqrt{256}*\sqrt{10}=16\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-16\sqrt{10}}{2*-5}=\frac{-50-16\sqrt{10}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+16\sqrt{10}}{2*-5}=\frac{-50+16\sqrt{10}}{-10} $
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