3/5x+3/10x=36/15

Solution for 3/5x+3/10x=36/15 equation:

3/5x+3/10x=36/15

We move all terms to the left:

3/5x+3/10x-(36/15)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We add all the numbers together, and all the variables

3/5x+3/10x-(+36/15)=0

We get rid of parentheses

3/5x+3/10x-36/15=0

We calculate fractions


(-1800x^2)/750x^2+450x/750x^2+225x/750x^2=0

We multiply all the terms by the denominator


(-1800x^2)+450x+225x=0

We add all the numbers together, and all the variables

(-1800x^2)+675x=0

We get rid of parentheses

-1800x^2+675x=0

a = -1800; b = 675; c = 0;
Δ = b2-4ac
Δ = 6752-4·(-1800)·0
Δ = 455625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{455625}=675$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(675)-675}{2*-1800}=\frac{-1350}{-3600}
=3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(675)+675}{2*-1800}=\frac{0}{-3600}
=0
$