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3/5x+1/5x+6=10
We move all terms to the left:
3/5x+1/5x+6-(10)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x+1/5x-4=0
We multiply all the terms by the denominator
-4*5x+3+1=0
We add all the numbers together, and all the variables
-4*5x+4=0
Wy multiply elements
-20x+4=0
We move all terms containing x to the left, all other terms to the right
-20x=-4
x=-4/-20
x=1/5
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