3/5x+(-2)=10

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Solution for 3/5x+(-2)=10 equation: 



3/5x+(-2)=10

We move all terms to the left:

3/5x+(-2)-(10)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



determiningTheFunctionDomain
3/5x-10+(-2)=0

We add all the numbers together, and all the variables

3/5x-12=0

We multiply all the terms by the denominator


-12*5x+3=0

Wy multiply elements

-60x+3=0

We move all terms containing x to the left, all other terms to the right

-60x=-3

x=-3/-60

x=1/20

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