If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3/5u-1/4=5/6u-5
We move all terms to the left:
3/5u-1/4-(5/6u-5)=0
Domain of the equation: 5u!=0
u!=0/5
u!=0
u∈R
Domain of the equation: 6u-5)!=0We get rid of parentheses
u∈R
3/5u-5/6u+5-1/4=0
We calculate fractions
(-180u^2)/480u^2+288u/480u^2+(-400u)/480u^2+5=0
We multiply all the terms by the denominator
(-180u^2)+288u+(-400u)+5*480u^2=0
Wy multiply elements
(-180u^2)+2400u^2+288u+(-400u)=0
We get rid of parentheses
-180u^2+2400u^2+288u-400u=0
We add all the numbers together, and all the variables
2220u^2-112u=0
a = 2220; b = -112; c = 0;
Δ = b2-4ac
Δ = -1122-4·2220·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-112}{2*2220}=\frac{0}{4440} =0 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+112}{2*2220}=\frac{224}{4440} =28/555 $
| -2x-88+8(x+2)=-9 | | 15z=9 | | (2x/7)+2=(3/2)-(x/7) | | 12(3x+4)=10(4x-12) | | 4(x–5)=4x–20 | | -2=1u+8/9 | | 7(u-8)=33(u+4) | | -2=u+8/9 | | -4/9x+34=-10 | | (5)/(2x+6)-(1)/(6)=(2)/(x-4) | | 8x-12-(5x-3)=0 | | -5/4=-4c+1/4 | | t-2/3=16/3 | | -3.6x+4.7=11.9 | | -0.10(46)+0.65x=0.05(x-20) | | -4x-11=-4(x+10) | | -0.3x+1.2=0.1x+3 | | 2(9x-59)=2(4x+10) | | -1/2(t+9+53/4t=3/8t | | 14x-13=-113+4x | | 1/7x+2=3/7 | | 7w=28;w= | | 0.15y+0.05(y+9000)=1250 | | x^-2-x^-1-42=0 | | 40+n×7.50=12.50×n | | 1/2x+4=5/2x+5/2 | | y+2=8/7 | | v-3/5=-1/5 | | 7y+3+2y=10y | | 4(8-5u)=-u-4 | | 1/2x-1=6 | | -1/4+w=7/8 |