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3/5t+1/5(40-t)=0
Domain of the equation: 5t!=0
t!=0/5
t!=0
t∈R
Domain of the equation: 5(40-t)!=0We add all the numbers together, and all the variables
t∈R
3/5t+1/5(-1t+40)=0
We calculate fractions
(15t(-)/(25t^2(-)+5t/(25t^2(-)=0
We calculate terms in parentheses: +(15t(-)/(25t^2(-)+5t/(25t^2(-), so:
15t(-)/(25t^2(-)+5t/(25t^2(-
We can not solve this equation
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