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3/5p+1/5(40-p)=p
We move all terms to the left:
3/5p+1/5(40-p)-(p)=0
Domain of the equation: 5p!=0
p!=0/5
p!=0
p∈R
Domain of the equation: 5(40-p)!=0We add all the numbers together, and all the variables
p∈R
3/5p+1/5(-1p+40)-p=0
We add all the numbers together, and all the variables
-1p+3/5p+1/5(-1p+40)=0
We calculate fractions
-1p+(15p(-)/(25p^2(-)+5p/(25p^2(-)=0
We calculate terms in parentheses: +(15p(-)/(25p^2(-)+5p/(25p^2(-), so:
15p(-)/(25p^2(-)+5p/(25p^2(-
We can not solve this equation
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