3/5g+1/4g=3

Solution for 3/5g+1/4g=3 equation:

3/5g+1/4g=3

We move all terms to the left:

3/5g+1/4g-(3)=0


Domain of the equation: 5g!=0

g!=0/5

g!=0

g∈R



Domain of the equation: 4g!=0

g!=0/4

g!=0

g∈R


We calculate fractions


12g/20g^2+5g/20g^2-3=0

We multiply all the terms by the denominator


12g+5g-3*20g^2=0

We add all the numbers together, and all the variables

17g-3*20g^2=0

Wy multiply elements

-60g^2+17g=0

a = -60; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-60)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-60}=\frac{-34}{-120}
=17/60
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-60}=\frac{0}{-120}
=0
$