3/5f=21

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Solution for 3/5f=21 equation: 



3/5f=21

We move all terms to the left:

3/5f-(21)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We multiply all the terms by the denominator


-21*5f+3=0

Wy multiply elements

-105f+3=0

We move all terms containing f to the left, all other terms to the right

-105f=-3

f=-3/-105

f=1/35

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