3/5=v+14/v+13

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Solution for 3/5=v+14/v+13 equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

3/5 = v+14/v+13 // - v+14/v+13

3/5-v-(14/v)-13 = 0

3/5-v-14*v^-1-13 = 0

-1*v^1-14*v^-1-62/5*v^0 = 0

(-1*v^2-62/5*v^1-14*v^0)/(v^1) = 0 // * v^2

v^1*(-1*v^2-62/5*v^1-14*v^0) = 0

v^1

(-62/5)*v-v^2-14 = 0

(-62/5)*v-v^2-14 = 0

DELTA = (-62/5)^2-(-14*(-1)*4)

DELTA = 2444/25

DELTA > 0

v = ((2444/25)^(1/2)-(-62/5))/(-1*2) or v = (-(-62/5)-(2444/25)^(1/2))/(-1*2)

v = ((2444/25)^(1/2)+62/5)/(-2) or v = (62/5-(2444/25)^(1/2))/(-2)

v in { ((2444/25)^(1/2)+62/5)/(-2), (62/5-(2444/25)^(1/2))/(-2)} 

v in { ((2444/25)^(1/2)+62/5)/(-2), (62/5-(2444/25)^(1/2))/(-2) }

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