3/5+7/5x=2/x^2

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Solution for 3/5+7/5x=2/x^2 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/5)*x+3/5 = 2/(x^2) // - 2/(x^2)

(7/5)*x-(2/(x^2))+3/5 = 0

(7/5)*x-2*x^-2+3/5 = 0

7/5*x^1-2*x^-2+3/5*x^0 = 0

(7/5*x^3+3/5*x^2-2*x^0)/(x^2) = 0 // * x^4

x^2*(7/5*x^3+3/5*x^2-2*x^0) = 0

x^2

(7/5)*x^3+(3/5)*x^2-2 = 0

(7/5)*x^3+(3/5)*x^2-2 = 0 // * 0

{ 1, -1, 2, -2, 5, -5, 10, -10 }

1

x = 1

7*x^3+3*x^2-10 = 0

1

x-1

7*x^2+10*x+10

7*x^3+3*x^2-10

x-1

7*x^2-7*x^3

10*x^2-10

10*x-10*x^2

10*x-10

10-10*x

0

7*x^2+10*x+10 = 0

DELTA = 10^2-(4*7*10)

DELTA = -180

DELTA < 0

x in { 1}

x = 1

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