3/5(x-8)=1/2(2x+4)

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Solution for 3/5(x-8)=1/2(2x+4) equation: 



3/5(x-8)=1/2(2x+4)

We move all terms to the left:

3/5(x-8)-(1/2(2x+4))=0



Domain of the equation: 5(x-8)!=0

x∈R





Domain of the equation: 2(2x+4))!=0

x∈R



We calculate fractions


(6x2/(5(x-8)*2(2x+4)))+(-5xx/(5(x-8)*2(2x+4)))=0



We calculate terms in parentheses: +(6x2/(5(x-8)*2(2x+4))), so:

6x2/(5(x-8)*2(2x+4))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-5xx/(5(x-8)*2(2x+4))), so:

-5xx/(5(x-8)*2(2x+4))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

6x^2-5xx=0

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