3/5(t+38)=-3(2-t

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Solution for 3/5(t+38)=-3(2-t equation: 



3/5(t+38)=-3(2-t

We move all terms to the left:

3/5(t+38)-(-3(2-t)=0



Domain of the equation: 5(t+38)!=0

t∈R



We add all the numbers together, and all the variables

3/5(t+38)-(-3(-1t+2)=0

We multiply all the terms by the denominator


-((-3(-1t+2))*5(t+38)+3=0

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