3/5(p-10)+16=p-12

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Solution for 3/5(p-10)+16=p-12 equation: 



3/5(p-10)+16=p-12

We move all terms to the left:

3/5(p-10)+16-(p-12)=0



Domain of the equation: 5(p-10)!=0

p∈R



We get rid of parentheses

3/5(p-10)-p+12+16=0

We multiply all the terms by the denominator


-p*5(p-10)+12*5(p-10)+16*5(p-10)+3=0

Wy multiply elements

-5p^2(p+60p(p+80p(p+3=0

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