3/5(n+25)=102/5n

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Solution for 3/5(n+25)=102/5n equation: 



3/5(n+25)=102/5n

We move all terms to the left:

3/5(n+25)-(102/5n)=0



Domain of the equation: 5(n+25)!=0

n∈R





Domain of the equation: 5n)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

3/5(n+25)-(+102/5n)=0

We get rid of parentheses

3/5(n+25)-102/5n=0

We calculate fractions


15n/(25n^2+625n)+(-510nn/(25n^2+625n)=0



We calculate terms in parentheses: +(-510nn/(25n^2+625n), so:

-510nn/(25n^2+625n

We multiply all the terms by the denominator


-510nn

Back to the equation:

+(-510nn)



We get rid of parentheses

15n/(25n^2+625n)-510nn=0

We multiply all the terms by the denominator


15n-510nn*(25n^2+625n)=0

We multiply parentheses

-12750n^3-318750n^2+15n=0

We do not support enpression: n^3

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