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3/5(3k+12)=3k
We move all terms to the left:
3/5(3k+12)-(3k)=0
Domain of the equation: 5(3k+12)!=0We add all the numbers together, and all the variables
k∈R
-3k+3/5(3k+12)=0
We multiply all the terms by the denominator
-3k*5(3k+12)+3=0
Wy multiply elements
-15k^2(3+3=0
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