3/5(2x+6)=1/2(3x-6)=

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Solution for 3/5(2x+6)=1/2(3x-6)= equation: 



3/5(2x+6)=1/2(3x-6)=

We move all terms to the left:

3/5(2x+6)-(1/2(3x-6))=0



Domain of the equation: 5(2x+6)!=0

x∈R





Domain of the equation: 2(3x-6))!=0

x∈R



We calculate fractions


(6x3/(5(2x+6)*2(3x-6)))+(-5x2/(5(2x+6)*2(3x-6)))=0



We calculate terms in parentheses: +(6x3/(5(2x+6)*2(3x-6))), so:

6x3/(5(2x+6)*2(3x-6))

We multiply all the terms by the denominator


6x3

We add all the numbers together, and all the variables

6x^3

We do not support expression: x^3

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