3/5(15d+20)-1/6)(18d-12)=38

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Solution for 3/5(15d+20)-1/6)(18d-12)=38 equation: 



3/5(15d+20)-1/6)(18d-12)=38

We move all terms to the left:

3/5(15d+20)-1/6)(18d-12)-(38)=0



Domain of the equation: 5(15d+20)!=0

d∈R





Domain of the equation: 6)(18d!=0

d∈R



We add all the numbers together, and all the variables

3/5(15d+20)-1/6)(18d=0

We calculate fractions


18d/(5(15d+20)*6)18d+(-5d1/(5(15d+20)*6)18d=0

We multiply all the terms by the denominator


18d+(-5d1=0

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