3/5(10w+20)-w=9(w+2)

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Solution for 3/5(10w+20)-w=9(w+2) equation: 



3/5(10w+20)-w=9(w+2)

We move all terms to the left:

3/5(10w+20)-w-(9(w+2))=0



Domain of the equation: 5(10w+20)!=0

w∈R



We add all the numbers together, and all the variables

-1w+3/5(10w+20)-(9(w+2))=0

We multiply all the terms by the denominator


-1w*5(10w+20)-((9(w+2)))*5(10w+20)+3=0



We calculate terms in parentheses: -((9(w+2)))*5(10w+20), so:

(9(w+2)))*5(10w+20



Wy multiply elements

-5w^2(1-((9(w+2)))*5(10w+20)+3=0

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