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3/4z-1/4-+1=2/4z+1
We move all terms to the left:
3/4z-1/4-+1-(2/4z+1)=0
Domain of the equation: 4z!=0
z!=0/4
z!=0
z∈R
Domain of the equation: 4z+1)!=0We add all the numbers together, and all the variables
z∈R
3/4z-(2/4z+1)-1/4=0
We get rid of parentheses
3/4z-2/4z-1-1/4=0
We calculate fractions
-1!=0
There is no solution for this equation
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