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3/4y=12y
We move all terms to the left:
3/4y-(12y)=0
Domain of the equation: 4y!=0We add all the numbers together, and all the variables
y!=0/4
y!=0
y∈R
-12y+3/4y=0
We multiply all the terms by the denominator
-12y*4y+3=0
Wy multiply elements
-48y^2+3=0
a = -48; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-48)·3
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-48}=\frac{-24}{-96} =1/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-48}=\frac{24}{-96} =-1/4 $
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