3/4y-1+2/3y+5=0

Solution for 3/4y-1+2/3y+5=0 equation:

3/4y-1+2/3y+5=0


Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R


We add all the numbers together, and all the variables

3/4y+2/3y+4=0

We calculate fractions


9y/12y^2+8y/12y^2+4=0

We multiply all the terms by the denominator


9y+8y+4*12y^2=0

We add all the numbers together, and all the variables

17y+4*12y^2=0

Wy multiply elements

48y^2+17y=0

a = 48; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·48·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*48}=\frac{-34}{96}
=-17/48
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*48}=\frac{0}{96}
=0
$