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3/4x=x-0.3
We move all terms to the left:
3/4x-(x-0.3)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
3/4x-x+0.3=0
We multiply all the terms by the denominator
-x*4x+(0.3)*4x+3=0
We multiply parentheses
-x*4x+1.2x+3=0
Wy multiply elements
-4x^2+1.2x+3=0
a = -4; b = 1.2; c = +3;
Δ = b2-4ac
Δ = 1.22-4·(-4)·3
Δ = 49.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.2)-\sqrt{49.44}}{2*-4}=\frac{-1.2-\sqrt{49.44}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.2)+\sqrt{49.44}}{2*-4}=\frac{-1.2+\sqrt{49.44}}{-8} $
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