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3/4x=1/x-2
We move all terms to the left:
3/4x-(1/x-2)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: x-2)!=0We get rid of parentheses
x∈R
3/4x-1/x+2=0
We calculate fractions
3x/4x^2+(-4x)/4x^2+2=0
We multiply all the terms by the denominator
3x+(-4x)+2*4x^2=0
Wy multiply elements
8x^2+3x+(-4x)=0
We get rid of parentheses
8x^2+3x-4x=0
We add all the numbers together, and all the variables
8x^2-1x=0
a = 8; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·8·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*8}=\frac{0}{16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*8}=\frac{2}{16} =1/8 $
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