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3/4x-5=x-25
We move all terms to the left:
3/4x-5-(x-25)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
3/4x-x+25-5=0
We multiply all the terms by the denominator
-x*4x+25*4x-5*4x+3=0
Wy multiply elements
-4x^2+100x-20x+3=0
We add all the numbers together, and all the variables
-4x^2+80x+3=0
a = -4; b = 80; c = +3;
Δ = b2-4ac
Δ = 802-4·(-4)·3
Δ = 6448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6448}=\sqrt{16*403}=\sqrt{16}*\sqrt{403}=4\sqrt{403}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-4\sqrt{403}}{2*-4}=\frac{-80-4\sqrt{403}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+4\sqrt{403}}{2*-4}=\frac{-80+4\sqrt{403}}{-8} $
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