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3/4x-4=4-2x
We move all terms to the left:
3/4x-4-(4-2x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
3/4x-(-2x+4)-4=0
We get rid of parentheses
3/4x+2x-4-4=0
We multiply all the terms by the denominator
2x*4x-4*4x-4*4x+3=0
Wy multiply elements
8x^2-16x-16x+3=0
We add all the numbers together, and all the variables
8x^2-32x+3=0
a = 8; b = -32; c = +3;
Δ = b2-4ac
Δ = -322-4·8·3
Δ = 928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{928}=\sqrt{16*58}=\sqrt{16}*\sqrt{58}=4\sqrt{58}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{58}}{2*8}=\frac{32-4\sqrt{58}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{58}}{2*8}=\frac{32+4\sqrt{58}}{16} $
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