3/4x-4=2/5x+10

Solution for 3/4x-4=2/5x+10 equation:

3/4x-4=2/5x+10

We move all terms to the left:

3/4x-4-(2/5x+10)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 5x+10)!=0

x∈R


We get rid of parentheses

3/4x-2/5x-10-4=0

We calculate fractions


15x/20x^2+(-8x)/20x^2-10-4=0

We add all the numbers together, and all the variables

15x/20x^2+(-8x)/20x^2-14=0

We multiply all the terms by the denominator


15x+(-8x)-14*20x^2=0

Wy multiply elements

-280x^2+15x+(-8x)=0

We get rid of parentheses

-280x^2+15x-8x=0

We add all the numbers together, and all the variables

-280x^2+7x=0

a = -280; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-280)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-280}=\frac{-14}{-560}
=1/40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-280}=\frac{0}{-560}
=0
$