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3/4x-2=-7-1/3x
We move all terms to the left:
3/4x-2-(-7-1/3x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(-1/3x-7)-2=0
We get rid of parentheses
3/4x+1/3x+7-2=0
We calculate fractions
9x/12x^2+4x/12x^2+7-2=0
We add all the numbers together, and all the variables
9x/12x^2+4x/12x^2+5=0
We multiply all the terms by the denominator
9x+4x+5*12x^2=0
We add all the numbers together, and all the variables
13x+5*12x^2=0
Wy multiply elements
60x^2+13x=0
a = 60; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·60·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*60}=\frac{-26}{120} =-13/60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*60}=\frac{0}{120} =0 $
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