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3/4x-2/5=1/2x-13
We move all terms to the left:
3/4x-2/5-(1/2x-13)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x-13)!=0We get rid of parentheses
x∈R
3/4x-1/2x+13-2/5=0
We calculate fractions
(-32x^2)/200x^2+150x/200x^2+(-100x)/200x^2+13=0
We multiply all the terms by the denominator
(-32x^2)+150x+(-100x)+13*200x^2=0
Wy multiply elements
(-32x^2)+2600x^2+150x+(-100x)=0
We get rid of parentheses
-32x^2+2600x^2+150x-100x=0
We add all the numbers together, and all the variables
2568x^2+50x=0
a = 2568; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·2568·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*2568}=\frac{-100}{5136} =-25/1284 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*2568}=\frac{0}{5136} =0 $
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