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3/4x-1/3=1/2x+5
We move all terms to the left:
3/4x-1/3-(1/2x+5)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+5)!=0We get rid of parentheses
x∈R
3/4x-1/2x-5-1/3=0
We calculate fractions
(-16x^2)/72x^2+54x/72x^2+(-36x)/72x^2-5=0
We multiply all the terms by the denominator
(-16x^2)+54x+(-36x)-5*72x^2=0
Wy multiply elements
(-16x^2)-360x^2+54x+(-36x)=0
We get rid of parentheses
-16x^2-360x^2+54x-36x=0
We add all the numbers together, and all the variables
-376x^2+18x=0
a = -376; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-376)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-376}=\frac{-36}{-752} =9/188 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-376}=\frac{0}{-752} =0 $
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