3/4x+7=-2/3x-1

Solution for 3/4x+7=-2/3x-1 equation:

3/4x+7=-2/3x-1

We move all terms to the left:

3/4x+7-(-2/3x-1)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 3x-1)!=0

x∈R


We get rid of parentheses

3/4x+2/3x+1+7=0

We calculate fractions


9x/12x^2+8x/12x^2+1+7=0

We add all the numbers together, and all the variables

9x/12x^2+8x/12x^2+8=0

We multiply all the terms by the denominator


9x+8x+8*12x^2=0

We add all the numbers together, and all the variables

17x+8*12x^2=0

Wy multiply elements

96x^2+17x=0

a = 96; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·96·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*96}=\frac{-34}{192}
=-17/96
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*96}=\frac{0}{192}
=0
$