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3/4x+5x=-9
We move all terms to the left:
3/4x+5x-(-9)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
5x+3/4x+9=0
We multiply all the terms by the denominator
5x*4x+9*4x+3=0
Wy multiply elements
20x^2+36x+3=0
a = 20; b = 36; c = +3;
Δ = b2-4ac
Δ = 362-4·20·3
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{66}}{2*20}=\frac{-36-4\sqrt{66}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{66}}{2*20}=\frac{-36+4\sqrt{66}}{40} $
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