3/4x+5=2/5x+26

Solution for 3/4x+5=2/5x+26 equation:

3/4x+5=2/5x+26

We move all terms to the left:

3/4x+5-(2/5x+26)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 5x+26)!=0

x∈R


We get rid of parentheses

3/4x-2/5x-26+5=0

We calculate fractions


15x/20x^2+(-8x)/20x^2-26+5=0

We add all the numbers together, and all the variables

15x/20x^2+(-8x)/20x^2-21=0

We multiply all the terms by the denominator


15x+(-8x)-21*20x^2=0

Wy multiply elements

-420x^2+15x+(-8x)=0

We get rid of parentheses

-420x^2+15x-8x=0

We add all the numbers together, and all the variables

-420x^2+7x=0

a = -420; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-420)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-420}=\frac{-14}{-840}
=1/60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-420}=\frac{0}{-840}
=0
$