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3/4x+5/12x-2/3=-3
We move all terms to the left:
3/4x+5/12x-2/3-(-3)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 12x!=0We add all the numbers together, and all the variables
x!=0/12
x!=0
x∈R
3/4x+5/12x+3-2/3=0
We calculate fractions
(-96x^2)/432x^2+324x/432x^2+180x/432x^2+3=0
We multiply all the terms by the denominator
(-96x^2)+324x+180x+3*432x^2=0
We add all the numbers together, and all the variables
(-96x^2)+504x+3*432x^2=0
Wy multiply elements
(-96x^2)+1296x^2+504x=0
We get rid of parentheses
-96x^2+1296x^2+504x=0
We add all the numbers together, and all the variables
1200x^2+504x=0
a = 1200; b = 504; c = 0;
Δ = b2-4ac
Δ = 5042-4·1200·0
Δ = 254016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{254016}=504$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(504)-504}{2*1200}=\frac{-1008}{2400} =-21/50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(504)+504}{2*1200}=\frac{0}{2400} =0 $
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