3/4x+5(2x-2)=1/2x+72

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Solution for 3/4x+5(2x-2)=1/2x+72 equation: 



3/4x+5(2x-2)=1/2x+72

We move all terms to the left:

3/4x+5(2x-2)-(1/2x+72)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 2x+72)!=0

x∈R



We multiply parentheses

3/4x+10x-(1/2x+72)-10=0

We get rid of parentheses

3/4x+10x-1/2x-72-10=0

We calculate fractions


10x+6x/8x^2+(-4x)/8x^2-72-10=0

We add all the numbers together, and all the variables

10x+6x/8x^2+(-4x)/8x^2-82=0

We multiply all the terms by the denominator


10x*8x^2+6x+(-4x)-82*8x^2=0

We add all the numbers together, and all the variables

6x+10x*8x^2+(-4x)-82*8x^2=0

Wy multiply elements

80x^3-656x^2+6x+(-4x)=0

We get rid of parentheses

80x^3-656x^2+6x-4x=0

We do not support expression: x^3

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