3/4x+2=5/6x+4

Solution for 3/4x+2=5/6x+4 equation:

3/4x+2=5/6x+4

We move all terms to the left:

3/4x+2-(5/6x+4)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 6x+4)!=0

x∈R


We get rid of parentheses

3/4x-5/6x-4+2=0

We calculate fractions


18x/24x^2+(-20x)/24x^2-4+2=0

We add all the numbers together, and all the variables

18x/24x^2+(-20x)/24x^2-2=0

We multiply all the terms by the denominator


18x+(-20x)-2*24x^2=0

Wy multiply elements

-48x^2+18x+(-20x)=0

We get rid of parentheses

-48x^2+18x-20x=0

We add all the numbers together, and all the variables

-48x^2-2x=0

a = -48; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-48)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-48}=\frac{0}{-96}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-48}=\frac{4}{-96}
=-1/24
$