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3/4x+2=4/6x
We move all terms to the left:
3/4x+2-(4/6x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(+4/6x)+2=0
We get rid of parentheses
3/4x-4/6x+2=0
We calculate fractions
18x/24x^2+(-16x)/24x^2+2=0
We multiply all the terms by the denominator
18x+(-16x)+2*24x^2=0
Wy multiply elements
48x^2+18x+(-16x)=0
We get rid of parentheses
48x^2+18x-16x=0
We add all the numbers together, and all the variables
48x^2+2x=0
a = 48; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·48·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*48}=\frac{-4}{96} =-1/24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*48}=\frac{0}{96} =0 $
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