3/4x+2=2x-8

Solution for 3/4x+2=2x-8 equation:

3/4x+2=2x-8

We move all terms to the left:

3/4x+2-(2x-8)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

3/4x-2x+8+2=0

We multiply all the terms by the denominator


-2x*4x+8*4x+2*4x+3=0

Wy multiply elements

-8x^2+32x+8x+3=0

We add all the numbers together, and all the variables

-8x^2+40x+3=0

a = -8; b = 40; c = +3;
Δ = b2-4ac
Δ = 402-4·(-8)·3
Δ = 1696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1696}=\sqrt{16*106}=\sqrt{16}*\sqrt{106}=4\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{106}}{2*-8}=\frac{-40-4\sqrt{106}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{106}}{2*-8}=\frac{-40+4\sqrt{106}}{-16}
$