3/4x+1=1/2x-7

Solution for 3/4x+1=1/2x-7 equation:

3/4x+1=1/2x-7

We move all terms to the left:

3/4x+1-(1/2x-7)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x-7)!=0

x∈R


We get rid of parentheses

3/4x-1/2x+7+1=0

We calculate fractions


6x/8x^2+(-4x)/8x^2+7+1=0

We add all the numbers together, and all the variables

6x/8x^2+(-4x)/8x^2+8=0

We multiply all the terms by the denominator


6x+(-4x)+8*8x^2=0

Wy multiply elements

64x^2+6x+(-4x)=0

We get rid of parentheses

64x^2+6x-4x=0

We add all the numbers together, and all the variables

64x^2+2x=0

a = 64; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·64·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*64}=\frac{-4}{128}
=-1/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*64}=\frac{0}{128}
=0
$