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3/4w-1/2w-4=11
We move all terms to the left:
3/4w-1/2w-4-(11)=0
Domain of the equation: 4w!=0
w!=0/4
w!=0
w∈R
Domain of the equation: 2w!=0We add all the numbers together, and all the variables
w!=0/2
w!=0
w∈R
3/4w-1/2w-15=0
We calculate fractions
6w/8w^2+(-4w)/8w^2-15=0
We multiply all the terms by the denominator
6w+(-4w)-15*8w^2=0
Wy multiply elements
-120w^2+6w+(-4w)=0
We get rid of parentheses
-120w^2+6w-4w=0
We add all the numbers together, and all the variables
-120w^2+2w=0
a = -120; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-120)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-120}=\frac{-4}{-240} =1/60 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-120}=\frac{0}{-240} =0 $
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