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3/4w+8=1/3w
We move all terms to the left:
3/4w+8-(1/3w)=0
Domain of the equation: 4w!=0
w!=0/4
w!=0
w∈R
Domain of the equation: 3w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
3/4w-(+1/3w)+8=0
We get rid of parentheses
3/4w-1/3w+8=0
We calculate fractions
9w/12w^2+(-4w)/12w^2+8=0
We multiply all the terms by the denominator
9w+(-4w)+8*12w^2=0
Wy multiply elements
96w^2+9w+(-4w)=0
We get rid of parentheses
96w^2+9w-4w=0
We add all the numbers together, and all the variables
96w^2+5w=0
a = 96; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·96·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*96}=\frac{-10}{192} =-5/96 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*96}=\frac{0}{192} =0 $
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