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3/4t-5/4=1/2t
We move all terms to the left:
3/4t-5/4-(1/2t)=0
Domain of the equation: 4t!=0
t!=0/4
t!=0
t∈R
Domain of the equation: 2t)!=0We add all the numbers together, and all the variables
t!=0/1
t!=0
t∈R
3/4t-(+1/2t)-5/4=0
We get rid of parentheses
3/4t-1/2t-5/4=0
We calculate fractions
6t/128t^2+(-64t)/128t^2+(-10t)/128t^2=0
We multiply all the terms by the denominator
6t+(-64t)+(-10t)=0
We get rid of parentheses
6t-64t-10t=0
We add all the numbers together, and all the variables
-68t=0
t=0/-68
t=0
Równanie nie ma rozwiązania
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